1. Find the molar mass of each element:
* Nitrogen (N): 14.01 g/mol
* Hydrogen (H): 1.01 g/mol
* Carbon (C): 12.01 g/mol
* Oxygen (O): 16.00 g/mol
2. Calculate the molar mass of ammonium carbonate:
* (NH₄)₂CO₃: 2(14.01 g/mol + 4(1.01 g/mol)) + 12.01 g/mol + 3(16.00 g/mol) = 96.09 g/mol
3. Calculate the mass of each element in one mole of ammonium carbonate:
* Nitrogen: 2 * 14.01 g/mol = 28.02 g/mol
* Hydrogen: 8 * 1.01 g/mol = 8.08 g/mol
* Carbon: 12.01 g/mol
* Oxygen: 3 * 16.00 g/mol = 48.00 g/mol
4. Calculate the percent composition of each element:
* Nitrogen: (28.02 g/mol / 96.09 g/mol) * 100% = 29.16%
* Hydrogen: (8.08 g/mol / 96.09 g/mol) * 100% = 8.41%
* Carbon: (12.01 g/mol / 96.09 g/mol) * 100% = 12.50%
* Oxygen: (48.00 g/mol / 96.09 g/mol) * 100% = 50.00%
Therefore, the percent composition of ammonium carbonate is:
* Nitrogen: 29.16%
* Hydrogen: 8.41%
* Carbon: 12.50%
* Oxygen: 50.00%
