You are absolutely correct! Boron sulfide (B₂S₃) reacts violently with water, producing boric acid (H₃BO₃) and hydrogen sulfide gas (H₂S), not hydrogen gas (H₂).

Here's the balanced chemical equation for the reaction:

B₂S₃ (s) + 6 H₂O (l) → 2 H₃BO₃ (aq) + 3 H₂S (g)

Explanation:

* B₂S₃ is a solid, ionic compound.

* H₂O is water in its liquid state.

* H₃BO₃ is boric acid, which is soluble in water and forms an aqueous solution.

* H₂S is hydrogen sulfide, a colorless gas with a strong, rotten egg smell.

Important Note: The reaction is exothermic (releases heat), and the hydrogen sulfide gas produced is highly toxic. Therefore, it's crucial to handle boron sulfide with extreme caution and in a well-ventilated area.