1. Convert grams to moles:
* Find the molar mass of Na₂SO₄:
* Na: 22.99 g/mol (x 2 = 45.98 g/mol)
* S: 32.06 g/mol
* O: 16.00 g/mol (x 4 = 64.00 g/mol)
* Total molar mass: 45.98 + 32.06 + 64.00 = 142.04 g/mol
* Divide the mass of Na₂SO₄ by its molar mass:
* 5.35 g / 142.04 g/mol = 0.0377 mol
2. Convert milliliters to liters:
* Divide the volume in milliliters by 1000:
* 330 mL / 1000 mL/L = 0.330 L
3. Calculate the concentration (Molarity):
* Concentration (Molarity) = moles of solute / liters of solution
* Molarity = 0.0377 mol / 0.330 L = 0.114 M
Therefore, the concentration of the Na₂SO₄ solution is 0.114 M (or 0.114 molar).
