1. Write the balanced chemical equation:

2 LiOH + CO₂ → Li₂CO₃ + H₂O

2. Determine the mole ratio:

The balanced equation shows that 2 moles of LiOH react with 1 mole of CO₂.

3. Calculate the moles of CO₂ needed to react with all the LiOH:

* Since the mole ratio is 2:1, you would need 0.15 moles of LiOH / 2 = 0.075 moles of CO₂ to react completely with all the LiOH.

4. Compare the available moles of CO₂ to the needed moles:

* You have 0.08 moles of CO₂, which is more than the 0.075 moles needed to react with all the LiOH.

Conclusion:

Since you have enough CO₂ to react with all the LiOH, LiOH is the limiting reagent.