Here's how to write the complete ionic equation for the reaction of NaOH(aq) and HCl(aq):

1. Identify the Reactants and Products:

* Reactants: NaOH(aq) and HCl(aq)

* Products: H₂O(l) and NaCl(aq)

2. Write the Balanced Molecular Equation:

NaOH(aq) + HCl(aq) → H₂O(l) + NaCl(aq)

3. Break Down Soluble Ionic Compounds into Ions:

* NaOH(aq) → Na⁺(aq) + OH⁻(aq)

* HCl(aq) → H⁺(aq) + Cl⁻(aq)

* NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

4. Write the Complete Ionic Equation:

Na⁺(aq) + OH⁻(aq) + H⁺(aq) + Cl⁻(aq) → H₂O(l) + Na⁺(aq) + Cl⁻(aq)

5. Cancel out Spectator Ions:

Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction. In this case, Na⁺ and Cl⁻ are spectator ions.

Final Complete Ionic Equation:

OH⁻(aq) + H⁺(aq) → H₂O(l)