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  • Calculating Ions in NaCl: A Step-by-Step Guide
    Here's how to determine the number of ions in a 6.58 mole sample of NaCl:

    1. Understand the Dissociation

    Sodium chloride (NaCl) dissolves in water to form sodium ions (Na+) and chloride ions (Cl-):

    NaCl(s) → Na+(aq) + Cl-(aq)

    This means each formula unit of NaCl produces two ions (one Na+ and one Cl-).

    2. Calculate the Number of Formula Units

    * Avogadro's number tells us there are 6.022 x 10^23 formula units in one mole of any substance.

    * Therefore, a 6.58 mole sample of NaCl contains:

    6.58 moles * (6.022 x 10^23 formula units/mole) = 3.96 x 10^24 formula units

    3. Calculate the Number of Ions

    * Since each formula unit of NaCl produces two ions, a 6.58 mole sample will have:

    3.96 x 10^24 formula units * 2 ions/formula unit = 7.92 x 10^24 ions

    Therefore, there are approximately 7.92 x 10^24 ions in a 6.58 mole sample of NaCl.

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