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  • Calculating the Number of Molecules in 0.358 mol of Trimellitic Acid
    Here's how to break down the calculation:

    1. Understanding the Formula

    * Trimellitic acid has the chemical formula C6H3(COOH)3. This means each molecule contains:

    * 6 carbon atoms (C)

    * 3 hydrogen atoms (H)

    * 3 carboxyl groups (COOH)

    2. Moles to Molecules

    * Avogadro's number: There are 6.022 x 10^23 molecules in one mole of any substance.

    * Calculating molecules: To find the number of molecules in 0.358 mol of trimellitic acid:

    * 0.358 mol * (6.022 x 10^23 molecules/mol) = 2.15 x 10^23 molecules

    3. Molecules to Atoms

    * Atoms per molecule: One molecule of trimellitic acid has 6 + 3 + 3(2) = 15 atoms.

    * Total atoms: To find the total number of atoms:

    * 2.15 x 10^23 molecules * 15 atoms/molecule = 3.23 x 10^24 atoms

    Therefore, in 0.358 mol of trimellitic acid, there are:

    * 2.15 x 10^23 molecules

    * 3.23 x 10^24 atoms

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