1. Identify the Elements and Their Atomic Masses:

* Ag (Silver): 107.87 g/mol

* Cr (Chromium): 52.00 g/mol

* O (Oxygen): 16.00 g/mol

2. Multiply the Atomic Mass of Each Element by Its Subscript in the Formula:

* Ag: 107.87 g/mol * 1 = 107.87 g/mol

* Cr: 52.00 g/mol * 1 = 52.00 g/mol

* O: 16.00 g/mol * 4 = 64.00 g/mol

3. Add the Masses Together:

107.87 g/mol + 52.00 g/mol + 64.00 g/mol = 223.87 g/mol

Therefore, the molar mass of AgCrO₄ is 223.87 g/mol.