Unbalanced Equation:
C₈H₁₈ + O₂ → CO₂ + H₂O + heat
Balancing the Equation:
1. Carbon (C): Start by balancing the carbon atoms. There are 8 carbon atoms on the left side (in C₈H₁₈), so we need 8 on the right side:
C₈H₁₈ + O₂ → 8CO₂ + H₂O + heat
2. Hydrogen (H): There are 18 hydrogen atoms on the left side (in C₈H₁₈). To get 18 on the right, we need 9 water molecules:
C₈H₁₈ + O₂ → 8CO₂ + 9H₂O + heat
3. Oxygen (O): Now, count the oxygen atoms on the right side. We have 16 from the CO₂ (8 x 2) and 9 from the H₂O (9 x 1), totaling 25 oxygen atoms. To get 25 on the left, we need 25/2 in front of the O₂:
C₈H₁₈ + (25/2)O₂ → 8CO₂ + 9H₂O + heat
4. Simplify (optional): It's not typical to have fractions in chemical equations. Multiply the entire equation by 2 to get whole numbers:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O + heat
Balanced Equation:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O + heat
What about "W" in your equation?
"W" likely represents work, which is also released during a combustion reaction. However, work is typically included as a change in enthalpy (ΔH) in the overall energy balance of the reaction.
Let me know if you'd like to learn more about combustion reactions or energy changes in chemical reactions!
