1. Write the Balanced Chemical Equation:

H₂CO₃ (aq) → H₂O (l) + CO₂ (g)

2. Calculate the Molar Mass of Carbonic Acid (H₂CO₃):

* H: 1.01 g/mol * 2 = 2.02 g/mol

* C: 12.01 g/mol

* O: 16.00 g/mol * 3 = 48.00 g/mol

* Total: 2.02 + 12.01 + 48.00 = 62.03 g/mol

3. Calculate the Moles of Carbonic Acid:

* Moles = mass / molar mass

* Moles = 6.20 g / 62.03 g/mol = 0.100 mol

4. Use the Mole Ratio from the Balanced Equation:

* The balanced equation shows a 1:1 mole ratio between H₂CO₃ and both H₂O and CO₂. This means for every 1 mole of H₂CO₃, you will get 1 mole of H₂O and 1 mole of CO₂.

5. Calculate the Mass of Water (H₂O) and Carbon Dioxide (CO₂):

* Molar Mass of H₂O: 18.02 g/mol

* Molar Mass of CO₂: 44.01 g/mol

* Mass of H₂O: 0.100 mol * 18.02 g/mol = 1.80 g

* Mass of CO₂: 0.100 mol * 44.01 g/mol = 4.40 g

Answer:

* 6.20 g of carbonic acid will form 1.80 g of water and 4.40 g of carbon dioxide.