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  • Calculating the Density of 1 M Sodium Hydroxide (NaOH)
    Here's how to calculate the density of a 1 molar sodium hydroxide (NaOH) solution:

    1. Understand Molarity

    * Molarity (M) is a unit of concentration that represents the number of moles of solute dissolved in 1 liter of solution.

    * In this case, a 1 M NaOH solution means there's 1 mole of NaOH dissolved in 1 liter of solution.

    2. Calculate the Mass of NaOH

    * The molar mass of NaOH is approximately 40 g/mol (23 g/mol for Na + 16 g/mol for O + 1 g/mol for H).

    * Since we have 1 mole of NaOH, the mass of NaOH in 1 liter of solution is 40 grams.

    3. Consider the Volume and Density

    * Density is mass per unit volume (usually grams per milliliter or g/mL).

    * We know the mass of NaOH (40 grams) and the volume of the solution (1 liter or 1000 mL).

    4. Calculate the Density

    * Density = Mass / Volume

    * Density = 40 grams / 1000 mL

    * Density = 0.04 g/mL

    Important Note: This calculation assumes that the volume of the solution is approximately equal to the volume of the water. In reality, dissolving NaOH in water causes a slight increase in volume. Therefore, the actual density of a 1 M NaOH solution will be slightly lower than 0.04 g/mL.

    To get a more accurate density:

    * You would need to experimentally measure the density of the solution using a density meter or a precise weighing method.

    * You can find density tables or online resources that provide densities of various concentrations of NaOH solutions.

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