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  • Benzoic Acid and 2-Propanol Reaction: Esterification & Mechanism
    Benzoic acid (C₆H₅COOH) will react with 2-propanol (CH₃CHOHCH₃) in the presence of an acid catalyst to form isopropyl benzoate (C₆H₅COOCH(CH₃)₂) and water. This is a classic esterification reaction.

    Here's a breakdown of the reaction:

    Reaction:

    C₆H₅COOH + CH₃CHOHCH₃ ⇌ C₆H₅COOCH(CH₃)₂ + H₂O

    Mechanism:

    1. Protonation of the alcohol: The acid catalyst (e.g., sulfuric acid) protonates the 2-propanol, making it a better leaving group.

    2. Nucleophilic attack: The oxygen of the carboxyl group in benzoic acid acts as a nucleophile and attacks the protonated 2-propanol.

    3. Proton transfer: A proton is transferred from the oxygen of the alcohol to the carboxyl group.

    4. Elimination of water: Water is eliminated from the molecule, forming the isopropyl benzoate ester.

    Conditions:

    * Acid catalyst: An acid catalyst like sulfuric acid is required to facilitate the reaction.

    * Heat: The reaction is usually carried out under reflux conditions (heating the mixture to its boiling point) to drive the equilibrium towards the product side.

    * Removal of water: Removing the water formed as a byproduct can further shift the equilibrium to the product side.

    Product:

    Isopropyl benzoate is a pleasant-smelling liquid commonly used in perfumes and flavorings.

    Note:

    The reaction is reversible, so some benzoic acid and 2-propanol will remain in equilibrium with the product. To maximize the yield of the ester, you can use an excess of one of the reactants or remove the water formed.

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