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  • Volume of Propane Gas: Calculation at Standard Conditions
    Here's how to calculate the volume occupied by 2 moles of propane gas at standard conditions:

    Understanding the Concepts

    * Standard Conditions (STP): Standard temperature and pressure are defined as 0°C (273.15 K) and 1 atm pressure.

    * Ideal Gas Law: The ideal gas law states that PV = nRT, where:

    * P = pressure (in atm)

    * V = volume (in liters)

    * n = number of moles

    * R = ideal gas constant (0.0821 L·atm/mol·K)

    * T = temperature (in Kelvin)

    Calculation

    1. Identify the known values:

    * n = 2 moles

    * P = 1 atm

    * T = 273.15 K

    * R = 0.0821 L·atm/mol·K

    2. Rearrange the ideal gas law to solve for volume (V):

    V = (nRT) / P

    3. Substitute the values and solve:

    V = (2 mol * 0.0821 L·atm/mol·K * 273.15 K) / 1 atm

    V = 44.8 L

    Therefore, 2 moles of propane gas would occupy a volume of 44.8 liters at standard conditions.

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