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  • Ammonia Production: Calculating Gram Yield from Nitrogen and Hydrogen
    Here's how to solve this problem:

    1. Balanced Chemical Equation:

    The balanced chemical equation for the reaction of nitrogen and hydrogen to form ammonia is:

    N₂(g) + 3H₂(g) → 2NH₃(g)

    2. Mole Ratio:

    The balanced equation tells us that 1 mole of N₂ reacts to produce 2 moles of NH₃.

    3. Calculate Moles of NH₃:

    Since we have 2.63 moles of N₂, we can use the mole ratio to calculate the moles of NH₃ produced:

    2.63 mol N₂ × (2 mol NH₃ / 1 mol N₂) = 5.26 mol NH₃

    4. Convert Moles to Grams:

    The molar mass of NH₃ is 17.03 g/mol. Multiply the moles of NH₃ by its molar mass to find the grams:

    5.26 mol NH₃ × (17.03 g NH₃ / 1 mol NH₃) = 89.6 g NH₃

    Therefore, 89.6 grams of NH₃ can be produced from 2.63 mol N₂ and excess H₂.

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