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  • Fehling's Test: Understanding the Reaction with Glucose
    When Fehling's solution is mixed with glucose, a red precipitate of cuprous oxide (Cu₂O) is formed. This reaction is a classic test for the presence of reducing sugars, like glucose.

    Here's a breakdown of what happens:

    * Fehling's solution is a mixture of two solutions:

    * Fehling's A: Aqueous solution of copper(II) sulfate (CuSO₄)

    * Fehling's B: Aqueous solution of potassium sodium tartrate (Rochelle salt) and a strong base like sodium hydroxide (NaOH).

    * Glucose is a reducing sugar, meaning it can donate electrons to other molecules.

    * The reaction:

    1. When Fehling's A and B are mixed, they form a complex ion of copper(II) ions and tartrate ions in an alkaline solution.

    2. The glucose acts as a reducing agent and donates electrons to the copper(II) ions in the complex.

    3. This reduces the copper(II) ions (Cu²⁺) to copper(I) ions (Cu⁺), which then precipitate out of solution as red cuprous oxide (Cu₂O).

    Key Observations:

    * Color change: The solution changes from a clear blue to a brick-red color.

    * Precipitate formation: A reddish-brown precipitate forms at the bottom of the test tube.

    Why this reaction is important:

    * Detecting reducing sugars: Fehling's test is widely used in chemistry and biochemistry to identify the presence of reducing sugars, such as glucose, fructose, and lactose.

    * Monitoring blood sugar levels: In clinical settings, similar tests are used to monitor blood sugar levels in individuals with diabetes.

    Additional Notes:

    * The reaction is specific to reducing sugars. Non-reducing sugars, like sucrose, will not give a positive Fehling's test.

    * The reaction is also influenced by factors like temperature and the concentration of the reagents.

    * It's important to note that Fehling's solution is considered a strong base and should be handled with caution.

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