- The atomic mass of barium (Ba) is 137.33 g/mol.
- The atomic mass of nitrogen (N) is 14.01 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
So, the mass of one mole of barium nitrate can be calculated as follows:
Mass of Ba(NO3)2 = (1 × 137.33 g/mol) + (2 × 14.01 g/mol) + (6 × 16.00 g/mol)
= 137.33 g/mol + 28.02 g/mol + 96.00 g/mol
= 261.35 g/mol
Therefore, the mass of one mole of barium nitrate is 261.35 grams.