C + O₂ → CO₂

Step 2: Determine the number of moles of carbon that reacted.

3 g C / 12.011 g/mol C = 0.2498 mol C

Step 3: Determine the number of moles of oxygen that reacted.

50 g O₂ / 32 g/mol O₂ = 1.5625 mol O₂

Step 4: Determine the limiting reactant.

The balanced chemical equation shows that 1 mole of carbon reacts with 1 mole of oxygen. In this case, we have 0.2498 mol of carbon and 1.5625 mol of oxygen. Therefore, carbon is the limiting reactant.

Step 5: Calculate the number of moles of carbon dioxide produced.

Since carbon is the limiting reactant, all of the carbon will be converted to carbon dioxide. Therefore, the number of moles of carbon dioxide produced will be equal to the number of moles of carbon that reacted:

0.2498 mol C

Step 6: Calculate the mass of carbon dioxide produced.

0.7495 mol CO₂ / 44.01 g/mol CO₂ = 33.18 g CO₂

Therefore, when 3 g of carbon are burnt in 50 g of oxygen, approximately 33.18 g of carbon dioxide are produced.