The molecular formula of ethanol is CH3CH2OH, which indicates that each molecule consists of 2 carbon atoms (C), 6 hydrogen atoms (H), and 1 oxygen atom (O).
Let's calculate the molar mass of ethanol:
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of ethanol (CH3CH2OH) = (2 x 12.01 g/mol) + (6 x 1.01 g/mol) + (1 x 16.00 g/mol)
= 24.02 g/mol + 6.06 g/mol + 16.00 g/mol
= 46.08 g/mol
Now, let's determine the mass percentage of oxygen in ethanol:
Mass percentage of oxygen = (Mass of oxygen in ethanol / Molar mass of ethanol) x 100%
= (16.00 g/mol / 46.08 g/mol) x 100%
= 34.72%
Since we know that the sample contains 3.36 g of oxygen, we can calculate the total sample size (in grams) using the mass percentage of oxygen:
Total sample size = (Mass of oxygen / Mass percentage of oxygen) x 100%
= (3.36 g / 34.72%) x 100%
= 9.68 g
Therefore, the total sample size for the ethanol sample containing 3.36 g of oxygen is 9.68 grams.
