To calculate the mass of 0.92 mol aluminum chromate, we need to know its molar mass. The molar mass of aluminum chromate (Al2(CrO4)3) can be calculated by adding the atomic masses of its constituent atoms.

The atomic mass of aluminum (Al) is 26.98 g/mol.

The atomic mass of chromium (Cr) is 51.996 g/mol.

The atomic mass of oxygen (O) is 15.999 g/mol.

In aluminum chromate, there are 2 atoms of aluminum, 3 atoms of chromium, and 12 atoms of oxygen. So, the molar mass of aluminum chromate can be calculated as:

Molar mass of Al2(CrO4)3 = 2(26.98 g/mol) + 3(51.996 g/mol) + 12(15.999 g/mol)

= 54.96 g/mol + 155.988 g/mol + 191.988 g/mol

= 402.936 g/mol

Now we can calculate the mass of 0.92 mol aluminum chromate by multiplying its molar mass with the number of moles:

Mass = 0.92 mol * 402.936 g/mol

= 371.344 g

Therefore, the mass of 0.92 mol aluminum chromate is approximately 371.344 g.