To find the number of sodium atoms represented in 15.59g of Na3PI4, we need to determine the molar mass of Na3PI4, the number of moles of Na3PI4 present in 15.59g, and then multiply that by the number of sodium atoms per mole of Na3PI4.

1. Calculate the molar mass of Na3PI4:

- Molar mass of Na = 22.99 g/mol

- Molar mass of P = 30.97 g/mol

- Molar mass of I = 126.90 g/mol

The molar mass of Na3PI4 = (3 x 22.99 g/mol) + (1 x 30.97 g/mol) + (4 x 126.90 g/mol) = 380.69 g/mol

2. Calculate the number of moles of Na3PI4 in 15.59g:

- Moles of Na3PI4 = Mass / Molar mass

- Moles of Na3PI4 = 15.59 g / 380.69 g/mol = 0.04096 mol

3. Calculate the number of sodium atoms per mole of Na3PI4:

- There are 3 sodium atoms per mole of Na3PI4.

4. Calculate the total number of sodium atoms in 15.59g of Na3PI4:

- Total number of sodium atoms = (Moles of Na3PI4) x (Number of sodium atoms per mole of Na3PI4)

- Total number of sodium atoms = 0.04096 mol x 3 atoms/mol = 0.12288 atoms

Therefore, there are approximately 0.12288 sodium atoms represented in 15.59g of phosphate,Na3PI4.