$$pH = 14 - pOH$$
Where pOH is the negative logarithm of the hydroxide ion concentration:
$$pOH = -\log[OH^-]$$
Given [OH^-] = 4:
$$pOH = -\log(4) = 0.602$$
Substituting pOH into the pH formula:
$$pH = 14 - 0.602 = 13.398$$
Therefore, the pH of the solution is approximately 13.398.