```

H2(g) + Cl2(g) → 2HCl(g)

```

From the equation, we can see that 1 mole of hydrogen reacts with 1 mole of chlorine to produce 2 moles of hydrochloric acid.

The molar mass of hydrogen is 2.016 g/mol, and the molar mass of chlorine is 35.45 g/mol.

Therefore, 2 pounds of hydrogen is equal to:

```

2 lb * (454 g/lb) / (2.016 g/mol) = 451 mol H2

```

And 73 pounds of hydrochloric acid is equal to:

```

73 lb * (454 g/lb) / (36.46 g/mol) = 631 mol HCl

```

Since 1 mole of hydrogen reacts with 1 mole of chlorine, we need 631 mol of chlorine to react with 631 mol of hydrogen.

Therefore, the weight of H2 g plus Cl2 g must be:

```

(451 mol H2 * 2.016 g/mol) + (631 mol Cl2 * 35.45 g/mol) = 45,391 g

```

Therefore, the total weight of H2(g) and Cl2(g) required for the reaction is approximately 45,391 grams.