Question: How many grams of NaOH are in 350 mL of a 2.5 M solution?

Answer: 21.25 grams of NaOH

Explanation:

To calculate the number of grams of NaOH in 350 mL of a 2.5 M solution, we can use the formula:

Mass of NaOH = Molarity × Volume of solution × Molecular weight of NaOH

First, we need to find the number of moles of NaOH present in 350 mL of the 2.5 M solution:

Moles of NaOH = Molarity × Volume of solution

Moles of NaOH = 2.5 mol/L × 0.350 L

Moles of NaOH = 0.875 mol

Now, we can calculate the mass of NaOH using its molecular weight (40 g/mol):

Mass of NaOH = Moles of NaOH × Molecular weight of NaOH

Mass of NaOH = 0.875 mol × 40 g/mol

Mass of NaOH = 35.0 grams

Therefore, there are 35.0 grams of NaOH in 350 mL of a 2.5 M solution.