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  • Iron and Copper Sulfate Reaction: Understanding Displacement & Products
    When iron reacts with copper sulfate (CuSO4), a displacement reaction takes place. Here's what happens:

    1. Formation of Iron Sulfate:

    Iron (Fe) atoms from the iron metal react with the sulfate ions (SO4^2-) from copper sulfate, resulting in the formation of iron sulfate (FeSO4). This compound is soluble in water and produces a green-colored solution.

    2. Displacement of Copper:

    As the iron atoms displace the copper ions (Cu^2+) from the copper sulfate compound, metallic copper is formed. This copper is deposited on the surface of the iron metal as a reddish-brown coating.

    3. Redox Reaction:

    This reaction is an example of a redox reaction, involving both oxidation and reduction. Iron undergoes oxidation as its oxidation state changes from 0 (in elemental iron) to +2 (in iron sulfate). On the other hand, copper undergoes reduction as its oxidation state decreases from +2 (in copper sulfate) to 0 (in metallic copper).

    Overall Reaction:

    The overall chemical equation for the reaction can be written as:

    Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)

    In summary, when iron reacts with copper sulfate, iron sulfate and metallic copper are formed. The iron atoms replace copper atoms in copper sulfate, leading to the formation of a green-colored iron sulfate solution and a reddish-brown copper coating on the iron metal.

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