Percentage of water = (Mass of water / Molar mass of compound) * 100
First, we need to calculate the molar mass of the compound BaOH2 8H2O:
Molar mass of BaOH2 8H2O = (137.33 g/mol) + (2 * 17.01 g/mol) + (8 * 18.02 g/mol) = 315.47 g/mol
Now, we can calculate the mass of water in the compound:
Mass of water = 8 * (18.02 g/mol) = 144.16 g
Finally, we can calculate the percentage of water in the compound:
Percentage of water = (144.16 g / 315.47 g) * 100 = 45.7%
Therefore, the percentage of water in BaOH2 8H2O to the nearest tenth is 45.7%.
