Here's the explanation:
In HBrO, bromine is bonded to oxygen and hydrogen. Oxygen typically has an oxidation number of -2, and hydrogen typically has an oxidation number of +1. Let "x" represent the oxidation number of bromine.
To determine the oxidation number of bromine, we can set up the equation:
-2 + x + 1 = 0
Solving for "x", we get:
x = +1
Therefore, the oxidation number of bromine in aqueous HBrO is +1.