No, the reaction between \(F_2\) and \(NaCl\) does not form \(NaF\) and \(Cl_2\). Instead, the reaction produces \(NaF\) and \(FCl\).

The reaction can be represented as:

$$ F_2 + 2NaCl → 2NaF + Cl_2 $$

In this reaction, \(F_2\) reacts with \(NaCl\) to form \(NaF\) and \(Cl_2\).

Therefore, the products of the reaction are \(NaF\) and \(Cl_2\), not \(NaF\) and \(Cl_2\).