Let's say we have the following reaction:
$$A + B → C + D \ \ \ \ \ \ \ ΔH = -100 kJ$$
If we want to multiply this reaction by 2, we would get:
$$2A + 2B → 2C + 2D \ \ \ \ \ \ ΔH = -200 kJ$$
So the enthalpy change for the multiplied reaction is simply the original enthalpy change multiplied by the factor we used to multiply the reaction.