The molar mass of lead (Pb) is 207.2 g/mol, and there are three lead atoms in the compound, so the total contribution from lead is 3 * 207.2 g/mol = 621.6 g/mol.
The molar mass of phosphorus (P) is 30.97 g/mol, and there are two phosphorus atoms in the compound, so the total contribution from phosphorus is 2 * 30.97 g/mol = 61.94 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol, and there are eight oxygen atoms in the compound, so the total contribution from oxygen is 8 * 16.00 g/mol = 128.00 g/mol.
Adding these contributions together, we get the molar mass of lead(III) phosphate:
Molar mass of Pb3(PO4)2 = 621.6 g/mol + 61.94 g/mol + 128.00 g/mol = 811.54 g/mol
Therefore, the molar mass of lead(III) phosphate is 811.54 g/mol.
