To calculate the molar mass of B10H14, we need to add up the atomic masses of each element in the compound multiplied by the number of atoms of each element.

The atomic masses of boron (B) and hydrogen (H) are:

- B: 10.811 atomic mass units (amu)

- H: 1.008 amu

So, the molar mass of B10H14 is:

(10 x 10.811 amu) + (14 x 1.008 amu) = 137.342 amu

Therefore, the molar mass of B10H14 is 137.342 grams per mole (g/mol).