To calculate the number of moles of ions produced when 2 mol Na2CO3 dissociate, we first need to determine the dissociation reaction for Na2CO3. When sodium carbonate (Na2CO3) dissolves in water, it dissociates into sodium ions (Na+) and carbonate ions (CO32-). The balanced化学方程for this dissociation is:

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Na2CO3 (aq) → 2 Na+ (aq) + CO32- (aq)

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From this equation, we can see that for every 1 mole of Na2CO3 that dissociates, 2 moles of Na+ ions and 1 mole of CO32- ions are produced. Therefore, if 2 mol of Na2CO3 dissociate, we can calculate the total number of moles of ions produced as follows:

Total moles of ions = (2 mol Na2CO3) × (2 moles of Na+ ions/1 mole of Na2CO3) + (2 mol Na2CO3) × (1 mole of CO32- ions/1 mole of Na2CO3)

Total moles of ions = 4 moles of Na+ ions + 2 moles of CO32- ions

Total moles of ions = 6 moles of ions

Therefore, when 2 mol Na2CO3 dissociate, a total of 6 moles of ions (4 moles of Na+ ions and 2 moles of CO32- ions) are produced.