1. Find the atomic weights of the elements:
* Boron (B): 10.811 g/mol
* Fluorine (F): 18.998 g/mol
2. Multiply the atomic weight of each element by its subscript in the formula:
* Boron (B): 10.811 g/mol * 1 = 10.811 g/mol
* Fluorine (F): 18.998 g/mol * 3 = 56.994 g/mol
3. Add the results together:
* 10.811 g/mol + 56.994 g/mol = 67.805 g/mol
Therefore, the molecular weight of BF3 is 67.805 g/mol.
