The exact value of the gravitational force, also known as the gravitational constant, or the Newton's gravitational constant, is approximately equal to:

```

G = 6.674 × 10^-11 N⋅(m/kg)^2

```

Therefore, the gravitational force between two objects of masses (m1) and (m2) separated by a distance (r) is given by:

```

F = Gm1m2/r^2

```

For the Sun, its gravitational force is determined by its enormous mass (approximately 1.988 × 10^30 kilograms). The greater the mass of an object, the stronger its gravitational force. However, the distance from the Sun also plays a crucial role in determining the strength of its gravitational pull.

To get a better understanding, let's calculate the gravitational force experienced by an object of mass 1 kilogram at the surface of the Sun. For this, we'll use the formula above and plug in the values of the Sun's mass (M) and the radius of the Sun (R = 6.957 × 10^8 meters):

```

F = GMm/R^2

F = (6.674 × 10^-11 N⋅(m/kg)^2) * (1.988 × 10^30 kg) * (1 kg) / (6.957 × 10^8 m)^2

F ≈ 274 N

```

So, an object of mass 1 kilogram at the surface of the Sun would experience a gravitational force of approximately 274 Newtons. This is about 28 times stronger than the gravitational force experienced by the same object at the surface of Earth.