To calculate the mass of 6.0 moles of sodium nitrate (NaNO3), we need to know its molar mass. The molar mass of a compound is the sum of the atomic masses of all the atoms in its chemical formula.

The chemical formula for sodium nitrate is NaNO3. This means that each molecule of sodium nitrate contains one atom of sodium (Na), one atom of nitrogen (N), and three atoms of oxygen (O).

The atomic mass of sodium is 22.99 grams/mole.

The atomic mass of nitrogen is 14.01 grams/mole.

The atomic mass of oxygen is 16.00 grams/mole.

So, the molar mass of sodium nitrate is:

(1 * 22.99 grams/mole) + (1 * 14.01 grams/mole) + (3 * 16.00 grams/mole) = 85.00 grams/mole

Now, we can calculate the mass of 6.0 moles of sodium nitrate by multiplying the molar mass by the number of moles:

(6.0 moles) * (85.00 grams/mole) = 510.00 grams

Therefore, the mass of 6.0 moles sodium nitrate (NaNO3) is 510.00 grams.