Understanding the Problem

We're dealing with a free-fall scenario where the glasses are dropped (initial velocity is zero) and fall under the influence of gravity. We need to find the height above the ground when the glasses hit.

Key Concepts

* Acceleration due to gravity (g): g = 9.8 m/s² (downwards)

* Free-fall equations:

* d = v₀t + (1/2)gt² (where d is distance, v₀ is initial velocity, t is time, and g is acceleration due to gravity)

Calculations

1. Find the total time of fall: Since the glasses hit the ground 2.28 seconds after the pen, and the pen was already in the same position, the glasses took 2.28 seconds to fall from the top of the stadium.

2. Calculate the distance the glasses fell:

* d = (1/2)gt²

* d = (1/2)(9.8 m/s²)(2.28 s)²

* d ≈ 25.4 m

3. Calculate the height above the ground when the glasses hit:

* Height above ground = Total stadium height - Distance the glasses fell

* Height above ground = 41.0 m - 25.4 m

* Height above ground = 15.6 m

Answer: The glasses were approximately 15.6 meters above the ground when they hit.