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  • Satellite Orbital Speed Calculation: Earth's Radius & Centripetal Acceleration
    Here's how to calculate the speed of a satellite orbiting just above the Earth's surface:

    Understanding the Concepts

    * Centripetal Acceleration: The acceleration required to keep an object moving in a circular path. It's directed towards the center of the circle.

    * Gravitational Force: The force of attraction between any two objects with mass. In this case, it's the force between the Earth and the satellite.

    * Orbital Speed: The speed at which an object must travel to maintain a stable orbit around another object.

    Formula

    The centripetal acceleration (a) of an object in circular motion is given by:

    a = v²/r

    where:

    * a = centripetal acceleration (9.8 m/s²)

    * v = orbital speed (what we want to find)

    * r = radius of the orbit (6375 km + a small amount for "just above" the surface, let's say 6378 km = 6,378,000 m)

    Solving for the Orbital Speed

    1. Rearrange the formula to solve for v:

    v = √(a * r)

    2. Plug in the values:

    v = √(9.8 m/s² * 6,378,000 m)

    3. Calculate the result:

    v ≈ 7905 m/s

    Converting to km/h:

    * 7905 m/s * (3600 s / 1 hour) * (1 km / 1000 m) ≈ 28,458 km/h

    Therefore, a satellite orbiting just above the Earth's surface needs to be moving at approximately 7905 m/s or 28,458 km/h to maintain a stable orbit.

    Important Note: This calculation assumes a perfectly circular orbit and neglects air resistance, which would significantly affect the actual speed required for a real-world satellite.

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