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  • Minimum Angular Velocity to Prevent Water Spillage in a Swinging Bucket
    Here's how to solve this problem:

    Understanding the Physics

    When you swing a bucket of water in a vertical circle, the water experiences two forces:

    * Gravity: Pulling the water downwards.

    * Centripetal force: The force that keeps the water moving in a circular path.

    To prevent spilling, the centripetal force must be *greater than or equal to* the force of gravity at the top of the circle.

    Setting up the Equations

    * Centripetal force (Fc): Fc = m * v^2 / r, where:

    * m is the mass of the water

    * v is the linear velocity of the water

    * r is the radius of the circle (the length of the student's arm)

    * Force of gravity (Fg): Fg = m * g, where:

    * g is the acceleration due to gravity (approximately 9.8 m/s^2)

    Solving for Angular Velocity

    1. Equal Forces: At the top of the circle, Fc = Fg to prevent spilling.

    m * v^2 / r = m * g

    2. Canceling mass: The mass of the water cancels out:

    v^2 / r = g

    3. Linear velocity to angular velocity: We need to relate linear velocity (v) to angular velocity (ω). The relationship is: v = r * ω

    4. Substituting and solving for ω:

    (r * ω)^2 / r = g

    r * ω^2 = g

    ω^2 = g / r

    ω = √(g / r)

    Calculating the Result

    * Convert arm length to meters: 63 cm = 0.63 m

    * Plug in values: ω = √(9.8 m/s^2 / 0.63 m) ≈ 3.95 rad/s

    Answer: The minimum angular velocity required to prevent spilling is approximately 3.95 rad/s.

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