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  • Calculating Fall Time on a Planet with 36 m/s² Gravity
    Here's how to solve this problem:

    Understanding the Concepts

    * Gravitational Acceleration (g): The acceleration due to gravity on this planet is 36 m/s². This means that the ball's speed increases by 36 meters per second every second it falls.

    * Initial Velocity (v₀): The ball is dropped from rest, so its initial velocity is 0 m/s.

    * Displacement (Δy): The ball falls 18 meters, so its displacement is -18 meters (negative because it's moving downward).

    Using the Kinematic Equation

    We can use the following kinematic equation to solve for the time (t):

    Δy = v₀t + (1/2)gt²

    Plugging in the Values

    * Δy = -18 m

    * v₀ = 0 m/s

    * g = 36 m/s²

    -18 = (0)t + (1/2)(36)t²

    -18 = 18t²

    Solving for Time (t)

    1. Divide both sides by 18: -1 = t²

    2. Take the square root of both sides: t = 1 second (we discard the negative solution since time cannot be negative)

    Answer: It takes 1 second for the ball to reach the ground.

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