• Home
  • Chemistry
  • Astronomy
  • Energy
  • Nature
  • Biology
  • Physics
  • Electronics
  • Magnetic Force on a Moving Proton: Calculating Proton Speed
    Here's how to solve this problem:

    Understanding the Concepts

    * Magnetic Force on a Charged Particle: A charged particle moving in a magnetic field experiences a force. The magnitude of this force is given by:

    * F = qvB sin θ

    * F is the magnetic force

    * q is the charge of the particle

    * v is the velocity of the particle

    * B is the magnetic field strength

    * θ is the angle between the velocity and the magnetic field

    * Right-Hand Rule: To determine the direction of the magnetic force, we use the right-hand rule.

    * Point your fingers in the direction of the velocity (east).

    * Curl your fingers towards the direction of the magnetic field (upward).

    * Your thumb will point in the direction of the force (south).

    Calculations

    1. Identify the knowns:

    * Force (F) = 8.8 x 10^-19 N

    * Charge of a proton (q) = 1.602 x 10^-19 C

    * Magnetic field strength (B) = 5.5 x 10^-5 T

    * Angle (θ) = 90° (since the velocity is east and the field is upward)

    2. Rearrange the magnetic force equation to solve for velocity (v):

    * v = F / (qB sin θ)

    3. Plug in the values:

    * v = (8.8 x 10^-19 N) / (1.602 x 10^-19 C * 5.5 x 10^-5 T * sin 90°)

    4. Calculate:

    * v ≈ 9.99 x 10^4 m/s

    Answer: The speed of the proton is approximately 9.99 x 10^4 m/s.

    Science Discoveries © www.scienceaq.com