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  • Speed vs. Velocity: A Snail's Journey - Average Speed & Velocity Explained

    Problem: The Speedy Snail

    Scenario: A snail named Shelly is crawling across a garden. She starts at a point 10 cm to the east of a sunflower and crawls 5 cm east in 10 seconds. She then turns around and crawls 3 cm west in 5 seconds.

    Questions:

    1. What is Shelly's average speed during the entire journey?

    2. What is Shelly's average velocity during the entire journey?

    Solution:

    1. Average Speed: Speed is the total distance traveled divided by the total time taken.

    * Total distance traveled = 5 cm (east) + 3 cm (west) = 8 cm

    * Total time taken = 10 seconds + 5 seconds = 15 seconds

    * Average Speed = 8 cm / 15 seconds = 0.53 cm/s

    2. Average Velocity: Velocity is the displacement (change in position) divided by the total time.

    * Displacement is the difference between the final and initial positions. Shelly ends up 2 cm east of the sunflower (10 cm + 5 cm - 3 cm = 12 cm, then 12 cm - 10 cm = 2 cm east).

    * Displacement = 2 cm east

    * Average Velocity = 2 cm east / 15 seconds = 0.13 cm/s east

    Answer:

    * Shelly's average speed is 0.53 cm/s.

    * Shelly's average velocity is 0.13 cm/s east.

    Key Points:

    * Speed is a scalar quantity, meaning it only has magnitude (how fast).

    * Velocity is a vector quantity, meaning it has both magnitude and direction.

    * Even though Shelly traveled a total distance of 8 cm, her final position was only 2 cm east of her starting point, which is her displacement.

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