1. Calculate the acceleration:

* Newton's Second Law: Force (F) = Mass (m) * Acceleration (a)

* Rearranging to find acceleration: a = F / m

* Plugging in the values: a = -3000 N / 3000 kg = -1 m/s²

* The negative sign indicates deceleration (slowing down).

2. Calculate the stopping time:

* Constant Acceleration Equation: v_f = v_i + at

* v_f = final velocity (0 m/s since the car stops)

* v_i = initial velocity (10 m/s)

* a = acceleration (-1 m/s²)

* t = time

* Rearranging to find time: t = (v_f - v_i) / a

* Plugging in values: t = (0 - 10) / -1 = 10 seconds

3. Calculate the stopping distance:

* Constant Acceleration Equation: d = v_i * t + (1/2) * a * t²

* Plugging in values: d = (10 m/s) * (10 s) + (1/2) * (-1 m/s²) * (10 s)²

* Simplifying: d = 100 m - 50 m = 50 m

Therefore, the stopping distance for the car is 50 meters.