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  • Uniform Velocity vs. Acceleration: Analyzing Displacement Proportional to Time Squared
    The body will be moving with uniform acceleration. Here's why:

    * Displacement and Acceleration: Displacement (change in position) is directly related to acceleration. If an object is accelerating, its displacement increases over time.

    * Proportional to the Square of Time: When displacement is proportional to the square of time, it means the displacement increases at an increasing rate. This is a hallmark of constant acceleration.

    Mathematical Explanation:

    Let's say the displacement (s) is proportional to the square of time (t):

    * s ∝ t²

    This can be written as:

    * s = kt² (where k is a constant of proportionality)

    Now, let's look at the relationship between displacement, velocity (v), and acceleration (a):

    * Velocity (v) is the rate of change of displacement: v = ds/dt

    * Acceleration (a) is the rate of change of velocity: a = dv/dt

    Differentiating the equation s = kt² twice with respect to time, we get:

    1. Velocity: v = ds/dt = 2kt

    2. Acceleration: a = dv/dt = 2k

    Since the acceleration (a) is a constant (2k), the body is moving with uniform acceleration.

    Example:

    Imagine a ball falling freely under gravity. Its displacement is proportional to the square of the time it falls. This is because gravity provides a constant acceleration to the ball.

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