• Home
  • Chemistry
  • Astronomy
  • Energy
  • Nature
  • Biology
  • Physics
  • Electronics
  • Calculating the Velocity of a Falling Quarter: A Physics Guide
    Here's how to calculate the velocity of a quarter dropped from a tower after 10 seconds:

    Understanding the Physics

    * Free Fall: When an object is dropped, it falls under the influence of gravity. This is called free fall.

    * Acceleration due to Gravity (g): The acceleration due to gravity on Earth is approximately 9.8 m/s². This means that the velocity of a falling object increases by 9.8 meters per second every second.

    * Initial Velocity (v₀): Since the quarter is dropped, its initial velocity is 0 m/s.

    Calculating the Velocity

    We can use the following equation:

    * v = v₀ + gt

    Where:

    * v is the final velocity

    * v₀ is the initial velocity (0 m/s)

    * g is the acceleration due to gravity (9.8 m/s²)

    * t is the time (10 seconds)

    Plugging in the values:

    * v = 0 + (9.8 m/s²)(10 s)

    * v = 98 m/s

    Therefore, the velocity of the quarter after 10 seconds is 98 m/s.

    Important Note: This calculation assumes no air resistance. In reality, air resistance would slow the quarter down, so the actual velocity would be slightly less than 98 m/s.

    Science Discoveries © www.scienceaq.com