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  • Calculating Tangential Acceleration of a Rotating Disk
    Here's how to solve this problem:

    1. Convert Units

    * Angular Speed: 75 revolutions per minute (rpm) needs to be converted to radians per second (rad/s).

    * 1 revolution = 2π radians

    * 1 minute = 60 seconds

    * Angular speed (ω) = (75 revolutions/minute) * (2π radians/revolution) * (1 minute/60 seconds) = 7.85 rad/s

    * Diameter to Radius: The diameter of the disk is 7.0 inches, so the radius (r) is half that:

    * r = 7.0 inches / 2 = 3.5 inches

    2. Calculate Angular Acceleration

    * Angular acceleration (α) is the rate of change of angular velocity. Since the bug starts from rest, its initial angular velocity (ω₀) is 0.

    * Use the following equation:

    * ω = ω₀ + αt

    * Where:

    * ω is the final angular velocity (7.85 rad/s)

    * ω₀ is the initial angular velocity (0 rad/s)

    * α is the angular acceleration (what we want to find)

    * t is the time (4.0 s)

    * Solve for α:

    * α = (ω - ω₀) / t = (7.85 rad/s - 0 rad/s) / 4.0 s = 1.96 rad/s²

    3. Calculate Tangential Acceleration

    * Tangential acceleration (at) is the acceleration of an object moving along a circular path. It's related to angular acceleration by:

    * at = α * r

    * Where:

    * α is the angular acceleration (1.96 rad/s²)

    * r is the radius of the circle (3.5 inches)

    * You'll need to convert the radius to meters for consistent units (1 inch = 0.0254 meters):

    * r = 3.5 inches * 0.0254 meters/inch = 0.0889 meters

    * Calculate the tangential acceleration:

    * at = (1.96 rad/s²) * (0.0889 meters) = 0.175 m/s²

    Therefore, the tangential acceleration of the bug is 0.175 m/s².

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