The electric force will also increase by a factor of 2.
Explanation:
Coulomb's Law describes the electric force between two point charges:
* F = k * (q1 * q2) / r²
Where:
* F is the electric force
* k is Coulomb's constant (a constant value)
* q1 and q2 are the magnitudes of the charges
* r is the distance between the charges
If you double one of the charges (let's say q1), the force becomes:
* F' = k * (2q1 * q2) / r²
This simplifies to:
* F' = 2 * (k * q1 * q2 / r²) = 2F
Therefore, doubling one charge doubles the electric force between the two charges.