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  • Projectile Motion Calculation: Determining Initial Velocity of a Kicked Rock
    Here's how to solve this problem:

    1. Understand the Physics

    * Projectile Motion: The rock is a projectile, meaning its motion is governed by gravity.

    * Horizontal and Vertical Motion: We need to analyze the horizontal and vertical components of the motion separately.

    * Constant Velocity: The horizontal velocity of the rock remains constant (ignoring air resistance).

    * Acceleration due to Gravity: The vertical acceleration is due to gravity (g = 9.8 m/s²).

    2. Calculate the Time of Flight

    * Vertical Motion: We know the vertical distance (450 meters) and the acceleration due to gravity (9.8 m/s²). We can use the following kinematic equation to find the time it takes for the rock to hit the water:

    * d = v₀t + (1/2)at² (where 'd' is distance, 'v₀' is initial vertical velocity, 't' is time, and 'a' is acceleration)

    * Since the initial vertical velocity is zero (you kick the rock horizontally), the equation simplifies to:

    * 450 m = (1/2)(9.8 m/s²)t²

    * Solve for 't':

    * t² = (450 m * 2) / 9.8 m/s²

    * t ≈ 9.58 s

    3. Calculate the Initial Horizontal Velocity

    * Horizontal Motion: We know the horizontal distance (32 meters) and the time of flight (9.58 s). We can use the following equation:

    * d = v₀t (where 'd' is distance, 'v₀' is initial horizontal velocity, and 't' is time)

    * Solve for 'v₀':

    * v₀ = d / t

    * v₀ = 32 m / 9.58 s

    * v₀ ≈ 3.34 m/s

    Therefore, the initial velocity of the rock was approximately 3.34 m/s.

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