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  • Vertical Velocity of a Horizontally Launched Projectile - Physics Problem
    Here's how to solve this problem:

    Understanding the Problem

    * Horizontal Launch: The projectile is fired horizontally, meaning its initial vertical velocity is 0 m/s.

    * Free Fall: Once the projectile leaves the gun, the only force acting on it is gravity, causing it to accelerate downwards.

    Key Concepts

    * Vertical Motion: We need to focus on the vertical component of the projectile's motion.

    * Acceleration due to Gravity: The acceleration due to gravity (g) is approximately 9.8 m/s². This means the projectile's downward speed increases by 9.8 m/s every second.

    * Constant Acceleration Equations: We can use the following equation to find the final vertical velocity:

    * *vf² = vi² + 2ad*

    Solution

    1. Identify knowns:

    * *vi* (initial vertical velocity) = 0 m/s

    * *a* (acceleration due to gravity) = 9.8 m/s²

    * *d* (vertical distance) = 71.0 m

    2. Plug the values into the equation:

    * *vf² = 0² + 2(9.8 m/s²)(71.0 m)*

    * *vf² = 1387.6 m²/s²*

    3. Solve for the final vertical velocity (vf):

    * *vf = √1387.6 m²/s² ≈ 37.2 m/s*

    Answer

    The magnitude of the vertical component of the projectile's velocity as it strikes the ground is approximately 37.2 m/s.

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