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  • Calculating the Momentum of a Proton at 0.86c: A Detailed Guide
    You're missing a crucial piece of information: the speed needs to be given in units, like meters per second (m/s). Let's assume the speed is 0.86c, where 'c' is the speed of light (approximately 3 x 10^8 m/s).

    Here's how to calculate the momentum of a proton moving at relativistic speeds:

    1. Relativistic Momentum:

    The momentum of a particle moving at relativistic speeds (close to the speed of light) is given by:

    ```

    p = γmv

    ```

    Where:

    * p is the momentum

    * γ is the Lorentz factor (accounts for relativistic effects)

    * m is the mass of the proton (1.6726 × 10^-27 kg)

    * v is the velocity of the proton (0.86c)

    2. Calculate the Lorentz Factor (γ):

    ```

    γ = 1 / √(1 - (v²/c²))

    ```

    Plug in the velocity (0.86c) and the speed of light (c):

    ```

    γ = 1 / √(1 - (0.86c)²/c²)

    γ = 1 / √(1 - 0.86²)

    γ ≈ 1.98

    ```

    3. Calculate the Momentum:

    Now, plug the values of γ, m, and v into the momentum equation:

    ```

    p = γmv

    p ≈ 1.98 * (1.6726 × 10^-27 kg) * (0.86 * 3 × 10^8 m/s)

    p ≈ 8.64 × 10^-19 kg m/s

    ```

    Therefore, the momentum of a proton moving at 0.86c is approximately 8.64 × 10^-19 kg m/s.

    Important Note: If the speed of the proton is actually 0.86 m/s (not 0.86c), then the momentum calculation would be much simpler, as the relativistic effects would be negligible at that speed. You would simply use the classical momentum formula:

    ```

    p = mv

    ```

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