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  • Projectile Motion: Where Will a Horizontally Thrown Ball Be After 1 Second?
    Here's how to break down the ball's motion one second later:

    Understanding the Motion

    * Horizontal Motion: The ball's horizontal velocity remains constant at 9 meters per second because there's no horizontal force acting on it (we're ignoring air resistance).

    * Vertical Motion: The ball is affected by gravity, causing it to accelerate downward at approximately 9.8 meters per second squared.

    Calculations

    * Horizontal Displacement: After one second, the ball will have traveled 9 meters horizontally (9 m/s * 1 s = 9 m).

    * Vertical Displacement:

    * The initial vertical velocity is 0 m/s (since it was thrown horizontally).

    * Using the equation: d = v₀t + (1/2)at²

    * d = vertical displacement

    * v₀ = initial vertical velocity (0 m/s)

    * t = time (1 s)

    * a = acceleration due to gravity (9.8 m/s²)

    * d = (0 m/s)(1 s) + (1/2)(9.8 m/s²)(1 s)² = 4.9 meters

    * The ball will have fallen 4.9 meters vertically.

    Summary

    One second after being thrown, the ball will be:

    * 9 meters horizontally from the cliff

    * 4.9 meters below the cliff

    Important Note: This assumes no air resistance. In reality, air resistance would slow the ball down slightly, affecting both the horizontal and vertical distances traveled.

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