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  • Calculating the Energy of a Uniformly Charged Spherical Shell
    Here's how to derive the energy of a uniformly charged spherical shell:

    1. Potential Due to the Shell

    * Inside the shell (r < R): The electric field inside a uniformly charged spherical shell is zero. Therefore, the potential is constant and equal to the potential on the surface of the shell.

    * Outside the shell (r > R): The electric field outside the shell is the same as that of a point charge Q located at the center of the shell. Using Coulomb's Law, the potential at a distance r from the center is:

    V(r) = kQ/r

    where k is Coulomb's constant (1/4πε₀).

    2. Calculating the Energy

    The energy stored in a charged system can be calculated using the following approach:

    * Energy = Work done to assemble the charge

    Imagine building up the charge on the shell gradually. At any moment, the potential due to the charge already on the shell is V(R) = kQ/R. To bring in an infinitesimal amount of charge dQ, the work done is:

    dW = V(R) dQ = (kQ/R) dQ

    To find the total energy, we integrate this expression from zero charge to the final charge Q:

    U = ∫dW = ∫₀^Q (kQ/R) dQ = (k/R) ∫₀^Q Q dQ

    U = (k/R) * (Q²/2)

    Therefore, the energy of a uniformly charged spherical shell is:

    U = (kQ²/2R) = (Q²/8πε₀R)

    Key Points

    * Symmetry: The spherical symmetry is crucial. The electric field and potential have simple expressions due to this symmetry.

    * Method of Assembly: The energy calculation relies on the idea of gradually assembling the charge, which allows us to use the potential at each step to calculate the work done.

    * Potential Energy: The energy stored in the charged shell represents the potential energy of the system due to the electrostatic forces between the charges.

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